Solve This Equations 3x+y=11, 5x-3y=9 (Waec 2015), Question Using Simultaneous Equation-Checkout!.

Good evening to you all the readers of this blog, I hope you all understand out last tutorial on ratio if yes, let go straight to the new topic.

The Ropic For Today Tutorial Is Simultaneous Equations.

Example 1

Solve this equations 3x+y=11, 5x-3y=9 (Waec 2015) question.

Solution by substitution method.

3x+y=11____________(equation 1)        

5x-3y=9_____________equation 2

From equation 1 Y=11-3x_____________equation 3

Substituting this value for y in equation 2

5x-3(11-3x)=9.

So therefore, 5x-33+9x=9.

So therefore, 14x=42

So therefore x=3.

Substituting this value for x in equation (3).

Y = eleven minus three multiply by three11-3(3)

Y = eleven minus nine (11-9).

Y =2

So therefore, x =3, and y = 2.

To know if its is a correct answer, kindly check by substituting both value in equation (1) and equation (2).

Equation (1)
3x+y

= Three multiply by three plus two (3×3+2).

=Nine plus two (9+2).

= eleven (11).

Equation (2).

5x-3y

= five multiply by three minus three multiply by two (5×3-3×2)

= fifteen minus six (15-6)

=nine (9).

Example 2.

Solve this equations 2x-3y=13, 5x+2y=4.

Solution by elimination method.

2x-3y=13.   equation 1

  5x+2y=4.    equation 2

Add equation (1) and equation (2) together.

  4x-6y= 26.  Equation (1).

15x+6y= 12 Equation (2).
____________
19x       =38.

So therefore, x= 38 divided by nine-then (38/19).

Equal to (=) 2

So therefore x = 2.

Substitute in equation (2).

5×2+2y=4

So therefore 2y= 4-10=-6.

So therefore y= -3.

Hope is  this simultaneous equation is clear to you all, if yes you can all try bellow question.

(1). Solve this equation
4/x+1/y=4, 2/x-3/y=9.

Find (x) and (y). Either using substitution or elimination method (waec 2016) question.

(2). Solve this equation 3x-2y+1=2x+5y-10=4x-3y.

Find (x) and (y).

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